In binomial expansion, the binomial coefficients of the second, third and fourth terms form an arithmetic sequence, and the constant term in the expansion can be obtained?

In binomial expansion, the binomial coefficients of the second, third and fourth terms form an arithmetic sequence, and the constant term in the expansion can be obtained?

Cn1+Cn3=2Cn2
n+n(n-1)(n-2)/6=n(n-1)
6+(n-1)(n-2)=6(n-1)
n^2-3n+8=6n-6
n^2-9n+14=0
N = 2 or n = 7
We can only solve it here first, because there is no binomial

Elden Ring Premiere

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