When the parabola y = 2x-1 is translated upward by 2 units, the analytic expression of the function is_

When the parabola y = 2x-1 is translated upward by 2 units, the analytic expression of the function is_

y=2X+1

Parabola y = 2 (X-5) 2 is obtained from parabola y = 2x & # 178; how to translate, and find its opening direction, fixed-point coordinates and axis of symmetry
There is also a question about how to translate the image of the function y = ¼ X & #178; - 5

Left plus right minus, y = 2x ^ 2 ----- > y = 2 (X-5) ^ 2, 5 units to the right. If the opening direction is upward, this is to see y = ax ^ 2 + BX + C A, and a > 0 is upward. Vertex coordinate is the coordinate to obtain the extremum. Here, if the opening is upward, imagine the parabola to know that the extremum is the minimum, and take (5,0) as

The parabola y = x ^ 2-6x + 5____ Translation_____ Then we get the parabola y = x ^ 2-2x-3

Shift 2 units to the right and 8 units up

The parabola y = 2x ^ 2 + 6x + 1 is translated by 2 units in the positive direction of the x-axis of the symmetric axis

y=2(x+3/2)²-7/2
y'=2(x-1/2)²-7/2