Given that the image of the function y = (K squared-k) x squared + KX + (K + 1) is a parabola, is the value range of K ≠ 1

Given that the image of the function y = (K squared-k) x squared + KX + (K + 1) is a parabola, is the value range of K ≠ 1

K square - K ≠ 0, K ≠ 1 and K ≠ 0

If the function value of parabola y = (2k + 1) x ^ has the minimum value, then the value range of K is

The function value of y = (2k + 1) x ^ 2 has the minimum value
2k+1>0
k>-1/2

Draw the image of parabola y = x square + 2x-3, and find the maximum or minimum value of function y = x square + 2x-3 in the following range respectively
①-2＜x＜0
②0≤x≤2

① The vertex of parabola is (- 1, - 4)
It can be seen from the image that the vertex is in the interval - 2

It is known that if a = 1 / 3, C = 2 + B and Y 3ax2 + 2bx + C, the minimum value of the parabola is - 3 in the interval of - 2 less than or equal to x less than or equal to 2
Finding the value of B

A: a = 1 / 3, C = 2 + B
Parabola y = 3ax & # 178; + 2bx + C = x & # 178; + 2bx + B + 2, - 2