What's the product of the difference between 62 and 46 multiplied by the quotient of 6 divided by 72?

What's the product of the difference between 62 and 46 multiplied by the quotient of 6 divided by 72?

(62-46)x(72/6)=192

Solution 1: a number in turn plus one tenth, multiplied by one tenth, minus one tenth, divided by one tenth, the quotient is one tenth,
Find the number
2: Seven out of thirteen of 39 is exactly three out of eleven of what?

1. (tenths * tenths + tenths) / tenths - tenths = 1
2.39 * 7 / 11 = 77

First, simplify, and evaluate: (x + 2) (x-3) + 3 (x-1) (x + 1) - (2x-1) (2x + 3), where x = minus one fifth

The original formula = (X & sup2; - X-6) + 3 (X & sup2; - 1) - (4x & sup2; + 4x-3)
=x²-x-6+3x²-3-4x²-4x+3
=-5x-6
=-5×(-1/5)-6
=-5

Simplification: x-2x + 3x-4x + 5x - +2001x-2002x

X-2X+3X-4X+5X-…… +2001x-2002x
=X(1-2+3-4+5-…… +2001-2002)
=X(-1-1-.-1)
=X(-1)*1001
=-1001X

If 2x + y = 1, what is 2012-4x-2y

2012-4x-2y=2012-2(2x+y)=2012-2=2010

4x(2x-y)-2y(y-2x)

Factorization:
4x(2x-y)-2y(y-2x)
=4x(2x-y)+2y(2x-y)
=(2x-y)(4x+2y)

Given 2x-y = 3, then 1-4x + 2Y=______ ．

∵2x-y=3，∴1-4x+2y=1-2（2x-y）=1-6=-5．

F (1 / x) = 5 / x + 2x ^ find f (x)?

f(1/x)=5/x+2x^2
Substitute x = 1 / X to get
f(x)=5x+2/x^2
Substitute x = x ^ 2 + 1 to get
f(x^2+1)=(x^2+1)+2/(x^2+1)^2
Hope to solve your problem

The odd function f (x) defined on R satisfies f (x + 3) = - 1 / F (x), and if - 3

f(x+3)=-1/f(x)
f(x+6)=
f[(x+3)+3]
=-1/f(x+3)
=f(x)
So t = 6
So the original formula = f (5.5 + 18 * 6)
=f(5.5)
=f(2.5+3(
=-1/f(2.5)
Odd function
=-1/[-f(-2.5)]
=1/(-5)
=-1/5

F (x) is an odd function over the domain R, f (x + 3) = - 1 / F (x) when x belongs to [- 3, - 2], f (x) = 2x, then the value of F (113.5) is
Note: it's an odd function

F (x + 3) = - 1 / F (x) so - 1 / F (x + 3) = f (x) f (x + 6) = f [(x + 3) + 3] = - 1 / F (x + 3) = f (x), that is, f (x + 6) = f (x) f (113.5) = f (107.5 + 6) = f (107.5), and so on, f (113.5) = f (107.5) = f (101.5) = =f(5.5)=f(2.5+3)=-1/f(2.5)-3