How to calculate the simple algorithm of 125 * (8 + 40) * 25?
125*(8+40)*25
=125*8*(1+5)*25
=1000*6*25
=1000*3*50
=150000
How to do 125 / 50 / 8 with simple algorithm?
125/(50/8)=125*8/50=(5*5*2)*(5*4)/(5*5*2)=20
(125/50)/8=125/(50*8)=(5*5*5)/(5*5*2*8)=1/16
125 × 25 × (8 × 4)
(125X8)X(25X4)=100000
Use the commutative law of multiplication! It's easy to get the easy ones together!
How to calculate (8 + 8 + 8 + 8) × 125 × 25
(8+8+8+8)×125×25
=8*4*125*25
=(8*125)*(4*25)
=1000*100
=That's 100000. 8 times 125 makes 1000. 4 times 25 makes 100. 1000 times 100 makes 100000
Use 4, 5, - 7, - 8 to calculate 24
((-8)÷4)×((-7)-5)=24
5.8.7.6 calculation 24
6*8-(7-5)=24
5,5,5,1 and 8,3,3,8 and 7,3,3,7
Hello!
2×6+5+7=24
2×5+8+6=24
3×7+(9-6)=24
3×8×(6-5)=24
3×8×(7-6)=24
3+5+7+9=24
2+6+7+9=24
3×2×8÷2=24
(-3+9)×8÷2=24
……
That's all I count. I tried my best
I play by hand. Thank you for your adoption
Calculation. 1 / 2 / 3 = 5 / 4 / 1 / 4 = 4 / 3 × 5 = 24 / 7 / 8 = 6 / 7 × 5 / 6 = 2 / 5 + 1 / 4 = 1 / 2 / 2 / 3 = 5 / 8-1 / 4=
I'm afraid I made mistakes. I just want to prove it. Our math teacher is very fierce. I have to see my parents for every wrong question. The summer vacation is coming to an end. I'm so poor that I haven't checked this question. Please help me. Thank you
3/2;5;20/3;21;5/7;13/20;3/4;3/8
Calculation (1 / 8 + 5 / 6-3 / 4) × (- 24)
(1/8+5/6-3/4)×(-24)
=1/8×(-24)+5/6×(-24)-3/4×(-24)
= -3-20+18
= -5
(x + 1) (x2-x + 1) + (X-2) (x2 + 2x + 4), where x = - 3 / 2
(x+1)(x2-x+1)+(x-2)(x2+2x+4),
=(x³+1)+(x³-8)
=2x³-7
When x = - 3 / 2
Original formula = - 27 / 4-7
=-55/4