Add brackets to the following formulas, and the result is equal to 1 1+2x3-4÷5=1 1x2﹢3-4+5÷6=1 1+2x3÷+4+5+6÷7=1 1+2÷3x4+5+6-7÷8=1 1x2+3x4-5+6+6-8÷9=1 The third line I wrote wrong is 1 + 2x3 △ 4 + 5 + 6 △ 7 = 1, sorry.

Add brackets to the following formulas, and the result is equal to 1 1+2x3-4÷5=1 1x2﹢3-4+5÷6=1 1+2x3÷+4+5+6÷7=1 1+2÷3x4+5+6-7÷8=1 1x2+3x4-5+6+6-8÷9=1 The third line I wrote wrong is 1 + 2x3 △ 4 + 5 + 6 △ 7 = 1, sorry.

[(1+2)x3-4]÷5=1
[1x(2﹢3)-4+5]÷6=1
1 + 2x3 △ 4 + 5 + 6 △ 7 = 1 wrong

Add brackets to the following formulas, and the result is equal to 1
1+2x3-4÷5=1
1x2﹢3-4+5÷6=1
1+2x3÷4+5+6÷7=1
1+2÷3x4+5+6-7÷8=1
1x2+3x4-5+6+7-8÷9=1
The fifth is wrong. I'm sorry
It should be 1x2 + 3 + 4-5 + 6 + 7-8 △ 9 = 1

[（1+2）x3-4]÷5=1
(1x2+3-4+5)÷6=1
[(1+2)x3÷(4+5)+6]÷7=1
[(1+2) ÷3x4+5+6-7]÷8＝1
1x2+3x4-5+6+7-8÷9=1
[1x（2+3）+4-5+6+7-8]÷9=1
The last one is 3 + 4, or it won't work out

1 + 2 * 3-4 / 5 = 1 add a bracket in the formula to make the calculation result equal to 1!
And 1 * 2 = 3-4 + 5 / 6 = 1
1+2*3/4+5+6/7=1
1+2/3*4+5+6-7/8=1
1*2+3+4-5+6+7-8/9=1

[(1+2)*3-4]/5=1
[1*(2+3)-4+5]/6=1
[(1+2)*3/(4+5)+6]/7=1
[(1+2)/3*4+5+6-7]/8=1
(1*2+3+4-5+6+7-8)/9=1

Add operational brackets and parentheses to the four numbers 5326 (each number must be used and can only be used once) and write an equation. The result of the equation is equal to 24
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5*6-(3*2)=24
2*6*(5-3)=24
(5-3+2)*6=24