The average number of the first group is 12.8, the average number of the second group is 10.2, and the average number of the two groups is 12.02. What is the ratio of the number of the first group to the number of the second group? It's urgent@@@@@@@@@@@@@~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ It's urgent~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ I need to explain the process. Excuse me

The average number of the first group is 12.8, the average number of the second group is 10.2, and the average number of the two groups is 12.02. What is the ratio of the number of the first group to the number of the second group? It's urgent@@@@@@@@@@@@@~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ It's urgent~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~ I need to explain the process. Excuse me

Let the first group have a number and the second group B number
The sum of the number of the first group = 12.8a, the sum of the number of the second group = 10.2b
The sum of the two groups = 12.8a + 10.2b = 12.02 * (a + b)
So we can get a: B

Given a number n, the number of divisors of n is represented by a sign B (n), find: 1. A (42). 2. B (42). 3. If a (n) = 8, what is the minimum of N?

A(42)=3
B(42)=3
(because 42 = 2 * 3 * 7)
3. If a (n) = 8, the minimum value of n is 256
Because 2 ^ 8 = 256