Given that three numbers a, B and C satisfy 1, ABC ≠ 0.2, a + B + C = ABC, please write two formulas that satisfy the conditions, Come on, it's no use if you're late. It's no more than 9 o'clock today. Thank you o. By the way, except 1 + 2 + 3 = 1 × 2 × 3 （-1）+（-2）+（-3）=（-1）×（-2）×（-3） Write one more of these two

Given that three numbers a, B and C satisfy 1, ABC ≠ 0.2, a + B + C = ABC, please write two formulas that satisfy the conditions, Come on, it's no use if you're late. It's no more than 9 o'clock today. Thank you o. By the way, except 1 + 2 + 3 = 1 × 2 × 3 （-1）+（-2）+（-3）=（-1）×（-2）×（-3） Write one more of these two

Subject condition constraint a, B, C are not 0, but only a + B + C = ABC an equation, you can arbitrarily set one of the parameters, such as a = 1, then the equation is 1 + B + C = BC, sort out the equation B = 1 + 2 / (C-1) about B, C, in another B, C any parameter, such as B = 4, you can get C = 5 / 3, you can get a formula is 1 + 4 + 5 / 3 = 20 / 3 = 1 * 4 * 5 / 3
And so on

There is a formula problem, ABC + CDC = DCFE, what are the numbers of a, B, C, D, e, f?
Vertical calculation is better

986+616=1602
987+717=1704
I've worked out two answers. I think it's very strange that there can't be two answers to this kind of question. You can do as you like, but these are the two answers

ABC three numbers, a: 4 = 5:12, 1 / 3 of B = 5 / 6 of C, product of C and 3 = product of 5 and 5 / 4
You can list the partial calculation in the exercise book or word, and then list the comprehensive calculation according to the partial calculation. Remember, find a, B, C are what value, column 3 comprehensive formula!

A:4=5:12,A=5/3
3C=5X5/4,C=25/12
1/3B=5/6C
B=125/24

There are two digits, the sum of which is ab, and the product of which is ABC. In the formula, a, B, C satisfy a = B + 1 = C + 2, a = several

A = 4
Let one of the numbers be X
Based on C, B = C + 1, a = C + 2
Then AB = 10C + 20 + C + 1 = 11C + 21
So another number = 11C + 21 - X
ABC
= 100(C + 2) + 10(C + 1) + C
= 111C + 210
= X(11C + 21 - X)
Change it into the quadratic equation of X, and write out the form of the root of X. because it is an integer, C and X can be obtained
The solution is C = 2, x = 16, 27
These two numbers are 16 and 27 respectively. Their sum is 43 and their product is 432
C = 2 ,B = 3,A = 4