The bottom of an isosceles right triangle is 10cm. What is its area in cm2?

The bottom of an isosceles right triangle is 10cm. What is its area in cm2?

Let the right edge be a centimeter, and the area of the triangle = a × a △ 2 = 12a2, because A2 + A2 = 102 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 2A2 = 100 & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; A2 = 50, that is, the area of the triangle is 12 × 50 = 25 (square centimeter). A: the area of the triangle is 25 square centimeter

If the length of a right side of a right triangle is √ 3cm and the length of the hypotenuse is √ 6cm, what is the square of the area of the right triangle

The other corner is √ [(√ 6) &# 178; - (√ 3) &# 178;] = √ 3
So the area is √ 3 × √ 3 △ 2 = 3 / 2

The perimeter of a right triangle is 12cm, and the side of a right triangle is 4cm
We should use Pythagorean theorem

Let the other right angle side be x, then the length of oblique side is 12-4-x = 8-x
From Pythagorean theorem
4*4 +x*x =(8-x)*(8-x)
Namely: 16 + X * x = 64-16x + X * x
16X = 48
X=3
Area = product of two right angles / 2 = 3 * 4 / 2 = 6
(bevel length 5)