If the three sides of a right triangle a, B and C are equal ratio and C is hypotenuse, then Sina =?

If the three sides of a right triangle a, B and C are equal ratio and C is hypotenuse, then Sina =?

(sinB)^2=sinA*sinC
C=90 B=90-A
1-(sinA)^2=sinA
(sinA)^2+sinA-1=0
sinA=(sqrt(5)-1)/2

Let the three sides of a right triangle be a, B, C. If C-B = B-A is greater than 0, what is the value of C-A divided by C + a
It's a little difficult

Pythagorean theorem combined with the condition that the trilateral ratio is 3:4:5, the answer is 0.25

If C-B = B-C is greater than 0, the value of C-A divided by C + A is obtained
I'm in a hurry