Help me to do a fraction calculation problem The square of (x + 1 / 2x) - (x-1 / 1-x + 1 / 1)

Help me to do a fraction calculation problem The square of (x + 1 / 2x) - (x-1 / 1-x + 1 / 1)


The square of (x + 1 / 2x) - (x-1 / 1-x + 1 / 1)
=(x+1)/x*[2x/(x+1)]²-[1/(x-1)-1/(x+1)]
=(x + 1) / X * 4x & # 178; / (x + 1) &# 178; - (x + 1-x + 1) / (X & # 178; - 1) make them have the same term
=4X / (x + 1) - 2 (X & # 178; - 1) reduction
=4X (x-1) / (X & # 178; - 1) - 2 / (X & # 178; - 1) make the denominator the same
=(4x²-4x-2)/(x²-1)
Good words, hope you adopt, thank you for your cooperation

Elden Ring Premiere

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