Given Tana = 3, the value of sin square a + sin square 2a is?

Given Tana = 3, the value of sin square a + sin square 2a is?

Since Tana = 3, Sina / cosa = 3sina = 3cosa (Sina) ^ 2 + (COSA) ^ 2 = 19 (COSA) ^ 2 + (COSA) ^ 2 = 1 (COSA) ^ 2 = 1 / 10 (Sina) ^ 2 = 9 / 10sin square a + sin square 2A = (Sina) ^ 2 + 4 (Sina) ^ 2 = 9 / 10 + 4 * (9 / 10) * (1 / 10) = 63 / 50

Tana = - 1 / 3, then the square a of sin + the square a of 2sinacosa-3cos=

Sina / cosa = Tana = - 1 / 3cosa = - 3sina is substituted into sin & sup2; a + cos & sup2; a = 1, then Sin & sup2; a = 1 / 10cos & sup2; a = 9 / 10sinacosa = Sina (- 3sina) = - 3sin & sup2; a = - 3 / 10, so on the circle = 1 / 10-6 / 10-27 / 10 = - 16 / 5

If sin (π / 6-A) = 1 / 3, then 2cos & # 178; (π / 6 + A / 2) - 1 is equal to?

From the angle doubling formula: 2cos & # 178; (π / 6 + A / 2) - 1 = cos (π / 3 + a)
cos(π/3+a)=cos[π/2-(π/6-a)]=sin(π/6-a)=1/3
So, 2cos & # 178; (π / 6 + A / 2) - 1 = 1 / 3

If 2sina = - 3cosa, then the quadrant of the terminal edge of 2sina is

Move it to - 2 / 3 Tana, and calculate the angle in quadrant 2 and 4 (because it is negative). But it seems that there is something missing in the title, and the symbols are different``

It is known that 1-tana / 1 + Tana = 3. 4sina-9cosa / 2sina-3cosa is calculated

From the previous equation, Tana = - 0.5, Cosa ≠ 0
Then divide the numerator and denominator by cosa
The original formula = (4tana-9) / (2tana-3) = (- 11) / (- 4) = 11 / 4 = 2.75 is obtained

3cosa + 2sina / 3cosa-2sina is known as Tana = 3

3cosa+2sina/3cosa-2sina
(the numerator and denominator divide COSA)
=3+2tana/3-2tana
Substituting Tana = 3
Original formula = 3 + 6 / 3-6
=-3
❤ your question has been answered ~ (> ^ ω)^

It is known that 2sina + 3cosa = 1.0

I'm glad to answer your question~
2sina+3cosa=1
2sina=1-3cosa
Two sides squared,
4sina^2=1+9cosa^2-6cosa
Because Sina ^ 2 + cosa ^ 2 = 1
4(1-cos^2)=1+9cosa^2-6cosa
So the solution is cosa = (3 + 4 √ 3) / 13,
Because 0

And √ 2sina = √ 3cosa, that is, Tana > 0 (a is the acute angle), that is, (COSA) ^ 2 = 2 / 5

Two sides square 2 (Sina) ^ 2 = 3 (COSA) ^ 2
(Sina) ^ 2 + (COSA) ^ 2 = 1, then (COSA) ^ 2 = 2 / 5

Given Tana = 2, find 2sina + cosa2sina − cosa + cos2a

∵tana=2，∴cos2a=15，∴2sina+cosa2sina−cosa+cos2a=2tana+12tana−1+cos2a=2815．

Given Tana = 2, find the value of 2sina + cosa / 2sina cosa

The numerator and denominator divide cosa2tana + 1 / 2tana-1 = 5 / 3 at the same time