Xiaoming and Xiaohua are running on the circular track. It takes 8 minutes for Xiaoming to run a lap and 10 minutes for Xiaohua to run a lap. Now it takes at least a few minutes for them to meet for the first time after they start from the starting point at the same time?

Xiaoming and Xiaohua are running on the circular track. It takes 8 minutes for Xiaoming to run a lap and 10 minutes for Xiaohua to run a lap. Now it takes at least a few minutes for them to meet for the first time after they start from the starting point at the same time?

It takes at least 409 minutes for them to meet for the first time

Xiao Ming and Xiao Dong keep running every morning. Xiao Ming runs 6 meters per second and Xiao Dong runs 4 meters per second
Xiaodong stands 10 meters in front of him. They both ride in the same direction at the same time. A few seconds later, Xiaoming catches up with Xiaodong

Assuming that Xiaoming catches up with Xiaodong after x seconds, the equation can be obtained according to the known conditions
6x-4x=10
x=5
So five seconds later, Xiao Ming catches up with Xiao Dong

Starting from the same starting point, Xiao Ming and Xiao Hua Run in the same direction along the 400 meter circular track. Xiao Ming runs 90 meters per minute, and Xiao Hua runs 110 meters per minute
The first time they met

Do they move in the same direction or in the opposite direction?
If it is reverse: 400 / (110 + 90) = 2 (minutes)
If it is in the same direction: 400 / (110-90) = 20 (minutes)

Xiaoming and Xiaohua run on the 400m circular road. They start from the same point at the same time and go in the opposite direction
Xiaoming and Xiaohua run on the 400m circular road. They start from the same point at the same time and go in opposite directions. Xiaoming runs 4.5m per second and Xiaohua runs 5.5m per second. After how many seconds, do they meet for the second time?

Suppose that after x seconds, they meet for the second time
4.5X + 5.5x = 400 × 2
10x=800
x=800÷10
x=80
A: after 80 seconds, they met for the second time