If the equation 3A / (1-x) + 1 / (x-1) = 1 has an increasing root, then the increasing root is? A and the value of? A is? God horse is zenggen! Hope to answer

If the equation 3A / (1-x) + 1 / (x-1) = 1 has an increasing root, then the increasing root is? A and the value of? A is? God horse is zenggen! Hope to answer

If you add a root, it is x = 1, a = 1 / 3. Adding a root is the value of X that you calculate and substitute it into the original equation. It is found that it is not true. If you substitute x = 1 and find that the denominator is 0, it is not in line with the reality, so it is adding a root

If the equation x / x + 1 - X-1 / X-2 = A / X & # 178; - X-2 has an increasing root, find the value of A
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x(x-2)-(x-1)(x+1)=a
x²-2x-x²+1=a
﹣2x+1=a
∵ the increasing root of the original fractional equation can only satisfy (x + 1) (X-2) = 0
The increasing root of the original fractional equation is x = - 1 or x = 2
When x = - 1, a = - 2x + 1 = - 2 × (- 1) + 1 = 3
When x = 2, a = - 2x + 1 = - 2 × 2 + 1 = - 3
A = 3 or - 3

If the equation 1-x 3A + X-1 1 = 1 has an increasing root, then the increasing root is a with a value of

3a of 1-x + 1 of X-1 = 1
(1-3a)/(x-1)=1
1-3a=x-1
x=2-3a
The root increase is 1
∴1=2-3a
a=1/3

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