If the equation MX + 3Y = 1-5x is a linear equation with one variable, then M emergency

If the equation MX + 3Y = 1-5x is a linear equation with one variable, then M emergency

mx+3y=1-5x
(m+5)x+3y=1
Because it's a linear equation of one variable
So m + 5 = 0
So m = - 5

Is 2x = 3Y a linear equation with one variable?
I think I'm an idiot
What about 7x + 5 = 6 (x-1)
And 1 / X-2 = x

How many unknowns are variables, and how many exponents are times! 2x and 3Y are bivariate, the last one is fractional equation, and the one in the middle is unary

Is 2x = 3Y a linear equation with one variable

2X = 3Y can be deformed to 2x-3y = 0
Because there are two unknowns x, y in the equation
So it's not a linear equation of one variable, it's a quadratic equation of two variables

It is known that (3K + 1) x ^ 2 + 2kx = - 3 is a quadratic equation of one variable with respect to X,
Find the solution set of inequality k-1 / 2 ≥ 4K + 1 / 3-1

Double six on both sides
3k-3≥8k+2-6
k≤1/5
On the quadratic equation of one variable of X
Then 3K + 1 ≠ 0
therefore
K ≤ 1 / 5 and K ≠ - 1 / 3