On the X inequality 3K (x-1) - 1 > - 8-3k (K ≠ 0), the solution set is x > 7, and the value of K is obtained

On the X inequality 3K (x-1) - 1 > - 8-3k (K ≠ 0), the solution set is x > 7, and the value of K is obtained

3kx-3k-1>-8-3k
3kx>-7
Divide both sides by 3K
The solution set is x > 7
The inequality sign does not change
So 3K > 0
k>0
And - 7 / 3K = 7
k=-1/3
Does not conform to k > 0
So there is no solution

Known 2 (K-2)

2k－4＜45k－105
43k＞101
k＞101/43
k（1－x）＜x－1
k－kx＜x－1
（k＋1）x＞k＋1
∵k＞101/43
∴k＋1＞0
∴ x＞1.

Given that (3K + 1) x ^ 2 + 2kx = - 3 is a quadratic equation of one variable with respect to x, find the solution set of the equation where k minus 1 is greater than or equal to 4K plus 1 minus 1

Given that (3K + 1) x ^ 2 + 2kx = - 3 is a quadratic equation of one variable with respect to x, find the solution set of the equation where k minus 1 is greater than or equal to 4K plus 1 minus 1
I said
1. Finding the equation is an inequality
2. Half K minus 1 --- Unknown K / 2 - 1; or (k-1) / 2!
3. One third of 4K plus one minus one is (4K + 1 / 3 - 1)

On the univariate linear equation of X (k-1) the square of X + (K-2) x + K-3 = 0 find k =?

∵ (k-1) x & # 178; + (K-2) x + K-3 = 0 is a one variable linear equation about X
It should conform to the general form of linear equation with one variable: ax + B = 0 (a ≠ 0)
From the undetermined coefficient method, k-1 = 0, K-2 ≠ 0
∴k=1