If the integer solutions of the inequality system 7x − m ≥ 06x − n < 0 about X are only 1,2,3, then the integer pairs (m, n) suitable for the inequality system share () A. 49 pairs B. 42 pairs C. 36 pairs D. 13 pairs
The solution set of 7x − m ≥ 06x − n < 0 is M7 ≤ x < N6, and the integer solutions of 7x − m ≥ 06x − n < 0 are only 1, 2, 3, 0 < M7 ≤ 1, 3 < N6 ≤ 4. The solution is 0 < m ≤ 7, 18 < n ≤ 24. The total number of 1, 2, 3, 4, 5, 6, 7 for 7x − m, and 19, 20, 21, 22, 23, 24 for N. there are 7 × 6 = 42 pairs of integers (m, n), so B is selected
If the integer solutions of the inequality system 7x − m ≥ 06x − n < 0 about X are only 1,2,3, then the integer pairs (m, n) suitable for the inequality system share ()
A. 49 pairs B. 42 pairs C. 36 pairs D. 13 pairs
The solution set of 7x − m ≥ 06x − n < 0 is M7 ≤ x < N6, and the integer solutions of 7x − m ≥ 06x − n < 0 are only 1, 2, 3, 0 < M7 ≤ 1, 3 < N6 ≤ 4. The solution is 0 < m ≤ 7, 18 < n ≤ 24. The total number of 1, 2, 3, 4, 5, 6, 7 for 7x − m, and 19, 20, 21, 22, 23, 24 for N. there are 7 × 6 = 42 pairs of integers (m, n), so B is selected
On the system of X inequalities 7x-m ≥ 0 6x-n
7x-m≥0 →x≥m/7
6x-n<0→x<n/6
m/7≤x<n/6
If the integer solution is only 1,2,3, let 1 ≤ x < 4,
m/7=1,3<n/6<4
m=7,18<n<24
m=7,n=19、20、21、22、23,
(m, n) there are 5 pairs of (7,19), (7,20), (7,21), (7,22), (7,23)
Please take the answer and support me
System of X inequalities 7x-m ≥ 0 6x-n
∵x<n/6
If n = 18
So x < 3
There won't be an integer solution of 3
And N = 24
If x is less than 4, there will be an integer solution of 3