A car with a mass of 2000 kg moves westward at a constant speed on a straight road, if the traction force it receives is 10000 n So what's the friction resistance? What's the direction?

A car with a mass of 2000 kg moves westward at a constant speed on a straight road, if the traction force it receives is 10000 n So what's the friction resistance? What's the direction?

When the car moves westward at a uniform speed, the force is balanced, and the following formula is: F resistance = f = 10000n
The direction is opposite to the direction of movement, eastward

When a 2T car runs at a constant speed on a flat horizontal road, the friction force on the car is 0.02 times of the weight of the car, then the traction force of the car is______ N. (take g = 10N / kg)

From the question, the gravity of the car: g = mg = 2000kg × 10N / kg = 2 × 104n, the friction of the car is 0.02 times of the weight of the car, so f = 0.02g = 0.02 × 2 × 104n = 400N, the car moves in a uniform straight line, so the traction and friction are a pair of balance force, f traction = f = 400N, so the answer is: 400