A truck with a weight of 6 × 103n runs at a constant speed on a straight road, and the resistance is 0.02 times of the weight of the truck (2) Can the car safely pass a bridge with a weight limit of 6T?

A truck with a weight of 6 × 103n runs at a constant speed on a straight road, and the resistance is 0.02 times of the weight of the truck (2) Can the car safely pass a bridge with a weight limit of 6T?


12.36N



When a car with a mass of 2 tons runs at a constant speed on a straight road, the friction force it receives is 0.15 times of the weight of the car


The two forces in horizontal direction are balanced. F traction force = f friction force = 0.15mg = 0.15 * 2000 * 10 = 3000n
The size of the car's traction is 3000n
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The mass is 6 times 10 cubic kilogram. The four-wheel vehicle drives at a constant speed of 10 meters per second on the straight road. The resistance in the process of driving is 0.0 of the vehicle weight
A four-wheel vehicle with a mass of 6 times 10 cubic kilogram drives at a constant speed of 10 meters per second on a straight road. The resistance during driving is 0.08 times the vehicle weight. The contact area between each tire and the ground is 0.05 square meter (G is 10N)
1. The gravity of the car
The distance a car passes in one minute
Pressure on the ground when three vehicles are stationary


G=mg=6000kg*10n/kg=60000n
One minute = 60 seconds, 60s * 10m / S = 600m
P=F/S=60000N/0.2M^2=300000Pa



The vehicle with a mass of 2 * 10 cubic kg runs at a speed of 10m / s, and the resistance in emergency braking is 1 / 3 of the vehicle weight
How many meters is the displacement of the car after four seconds from braking?
Seek the meaning of the problem analysis and problem-solving steps!


Reverse thinking should be used for braking problems,
The resistance is 1 / 3 times of the vehicle weight, and the resistance f = 1 / 3mg can be calculated
Then calculate the deceleration acceleration a = f / M = 1 / 3G, braking time < 4S
So within four seconds, the car has stopped
V²=2ax
x=15m
Note that the time in the braking problem must be the time spent in the actual emergency braking, not the time given by the topic