The tractive force of a 5000kg car on a straight road is 16170n and the resistance is 980n. The acceleration of the car is calculated

The tractive force of a 5000kg car on a straight road is 16170n and the resistance is 980n. The acceleration of the car is calculated

16970-980=15190
15190/5000=3.038m/s^2

What physical knowledge does Newton use in his steam car design

… I found that someone had answered
When the water in the steam engine boils, the air in the cylinder expands rapidly and pushes the piston in the cylinder
The piston drives the axle connected to the rear, and the left and right sides of the lever connected with it are the wheels of the car, which makes the car move. Because the distance of the piston is too long, the volume of gas in the cylinder increases and the pressure decreases, and the water stops boiling at 1 standard atmospheric pressure, The boiling point of liquid decreases with the decrease of pressure
Through the action of fuel, water is boiling again, driving the piston and its axle, making the car move again and again
The physical knowledge is that the force between objects is mutual, the energy is conserved, and the applied force is the ground. The friction between the tire and the ground, that is, the traction with the car, is a pair of balance forces

Knowledge of physics in cars

1、 Mechanics: 1. The chassis of the car has a large mass, which can reduce the center of gravity of the car and increase the stability of the car when driving. 2. The body of the car is streamlined to reduce the resistance of the car when driving. 3. The driving force of the car - the friction between the ground and the driving wheel (the driving wheel and the driven wheel and the ground

A car runs at a constant speed of 70 kilometers on a straight road. The speed of the car is 72 kilometers per hour. The total consumption of gasoline is 6L. How many kilowatts is the power of the car,
Condition tank volume 50L
Gasoline density 700 kg / m3
The calorific value of gasoline is 4.6 × 10000000 coke / kg
40% of internal energy converted into mechanical energy by complete combustion of fuel

Idea: first calculate how much gasoline A is consumed in one second, and then calculate how much mechanical energy B can be provided by A
Total time: 70 / 72 = 0.9722 hours = 3500 seconds
Gasoline consumption per second: a = 6 liters / 3500 = 6000 ml / 3500 = 1.714 ml
Mechanical energy: B = a * 0.7 * 4.6 * 4.6 * 10000 * 40% = 220.8kw
End of solution