When a car is running at a constant speed, the engine traction is 2000 N and the speed is 108 km / h. The resistance of the car is calculated

When a car is running at a constant speed, the engine traction is 2000 N and the speed is 108 km / h. The resistance of the car is calculated

2000N

A car runs at a constant speed on a straight road, the engine traction is 2000N, and the speed is 30m / s
(1) The distance a car travels at a constant speed for 10 minutes
(2) The work done by the traction force in 10 minutes
(3) The power of traction f to do work

（1）30×10×60 = 18000m = 18km
（2）2000N×18000m = 36×10^6 N·m
(3) The power is 2000N × 30m / S = 60000 n · M / S = 60kW

A car weighs 2000 n, the traction of the engine is 400 N, and the car passes through a 2400 m long straight bridge at a constant speed in 2 min. the following are obtained: 1. What is the speed of the car
The traction force of a car's 2000N engine is 400N. The car passes a 2400m long straight bridge at a constant speed for 2min
1. What is the speed of the car?
2. How much resistance does the car suffer?
3. If the car wants to speed up,

1.2400/2/60=20m/s
2.400N
3. Step on the accelerator to increase the traction of the engine, so that the traction is greater than the resistance

When the truck is driving on the level road, the engine traction is not enough
The truck runs on the horizontal highway (1) if the engine traction force is 2x10 ^ 3N, it runs 54km in one hour, calculate its average power in this period
(2) If the engine power of the truck is 66kw, the resistance of the truck at the maximum speed and constant speed is 3x10 ^ 3N, find the maximum speed of the truck

We must know that the formula of power is p = w / T. so we say w = FS = 2x10 ^ 3nx54000 = 1.08x10 ^ 8j. Then p = w / T = 1.08x10 ^ 8j / 3600s = 30kW
From P = FV, v = P / F = 66kw / 3x10 ^ 3N = 22m / s