When a car runs at a constant speed of 72km / h, the traction power of the car is 6 times 10 small 4W, and the car runs at a constant speed of 2000m at this speed to get the traction power

When a car runs at a constant speed of 72km / h, the traction power of the car is 6 times 10 small 4W, and the car runs at a constant speed of 2000m at this speed to get the traction power

V=72km/h=20m/s
t=S/V=2000m/(20m/s)=100s
Work of automobile traction w = Pt = (6 * 10 ^ 4) * 100 = 6 * 10 ^ 6J
Because w = FS
So f = w / S = (6 * 10 ^ 6) / 2000 = 3 * 10 ^ 3 N
If only for F
Then p = w / T = FS / T = FV
So f = P / v = (6 * 10 ^ 4) / 20 = 3 * 10 ^ 3N

When a car with a weight of 1.5 × 10 and a power of 4 N drives at a speed of 60 km / h on a horizontal road at a constant speed, the traction force it receives is 2000 n, then the resistance it receives is 200 n____ N. When parking on the horizontal road, the support is___ N speed

The resistance is 2000N, because it is driving at a constant speed, the traction force = resistance
The support force is 1.5 × 10 to the fourth power n, so the support force is equal to the gravity on the horizontal road

When a 104n car moves in a straight line at a constant speed on the road, its resistance is 0.03 times of the weight of the car. What is the traction force of the engine?

Because the car moves in a straight line at a constant speed, the traction and resistance of the car are a pair of balance forces, so the traction force of the car is f = f = 0.03g = 0.03 × 104n = 300N. A: the traction force of the car engine is 300N