X ^ 7 * (- x ^ 2) ^ - 3 3x (2x 6) - (x-3) (x 2) where x = 2

X ^ 7 * (- x ^ 2) ^ - 3 3x (2x 6) - (x-3) (x 2) where x = 2


X^7*(-X^2)^-3
=-x^7*x^-6
=-x
3X(2x+ 6)-(x-3)(x+ 2)
=-6x²+18x-x²+x+6
=-7x²+18x+6
=-7x2²+18x2+6
=-28+36+6
=14
Click comment in the upper right corner, and then you can select satisfied, the problem has been solved perfectly



(x-4)(2x-5)-(3x-2)(x+6)


Original form
=2x²-13x+20-(3x²+16x-12)
=-x²-29x+32



(2x-5)/6>3x-(x+2)/4


(2x-5)/6>3x-(x+2)/4
Multiply both sides by 12
2(2x-5)>36x-3(x+2)
4x-10>36x-3x-6
33x-4x<-10+6
29x<-4
x<-4/29



3x + 6 × 2.5 = 16-x equation