5x ^ + 30x + 45-5 x-3 5 = 0 help to calculate

5x ^ + 30x + 45-5 x-3 5 = 0 help to calculate

5x ^ 2 + 30x + 45 - radical 5x-3 radical 5 = 0
5 (x + 3) ^ 2-radical 5 (x + 3) = = 0
(x + 3) [5 (x + 3) - radical 5] = 0
(x + 3) (5x + 15 radical 5) = 0
X1 = - 3, X2 = - 3 + (radical 5) / 5

5x+2(x+6)=3(8+x)+2x

5x + 2x + 12 = 24 + 3x + 2x bracket expansion
7x + 12 = 24 + 5x add
7x-5x = 24-12 coefficients and numbers move to the same side
2x=12
x=6

（1）6+2（x-3)=X (2)8-2(x-7)=x-(x-4) (3)2x-(1.5x-1)=2(1.5x-1)

（1）6+2（x-3)=X
6+2x-6=x
2x-x=0
x=0
(2)8-2(x-7)=x-(x-4)
8-2x+14=x-x+4
-2x=-18
x=9
(3)2x-(1.5x-1)=2(1.5x-1)
2x-3(1.5x-1)=0
2x-4.5x=-3
-2.5x=-3
x=6/5

Fill in the following table x 7 () 7 / 2 () 16.4 () y () 2 / 3 () 9.3 () 1.5 according to 5x = 3Y
Fill in the following table according to 5x = 3Y
X 7 ( )7/2 ( ) 16.4 ( )
y （ ） 2/3 （ ) 9.3 （ ） 1.5

X 7 ( 2/5 ) 7/2 ( 5.58 ) 16.4 ( 0.9 )
y （35/3 ） 2/3 （ 35/6 ) 9.3 （ 82/3 ） 1.5