What number can divide 18 and 24

What number can divide 18 and 24


The common divisor of 18 and 24



If you divide a number by 18, 24, and 30, you can divide it. The maximum number is
60 seconds


360



If ABC is a non-zero natural number and a > b, then a of C minus B of C = what fraction
1: A stationery store made about 50000 yuan last year. How much do you think the stationery store could earn at most?
2: Write down the meaning of the following forms
One quarter minus 0.1
Quarter plus 0.1
3.5 times one eighth
3.5 divided by one eighth


A / C-B / C = (a-b) / C1. At least 45000 yuan, at most 54000 yuan (rounded) 2.1/4-0.1 = 0.25-0.1 = 0.153.1/4 + 0.1 = 0.25 + 0.1 = 0.354.3.5 x 1 / 8 = 3.5 x 0.125 = 0.43755.3.5 △ 1 / 8 = 3.5 △ 0.125 = 28. I hope it can help you. If you have any questions, please continue to ask



It is known that a, B and C are three different natural numbers, and a + B + C = 11. Then the maximum value of a × B × C is______ The minimum value is______ .


When a, B and C are 2, 4 and 5 respectively, the maximum value of a × B × C is 2 × 4 × 5 = 40. When one of a, B and C is 0, the minimum value of a × B × C is 0, so the answer is 40, 0



It is known that ABC is a non-zero natural number, satisfying B + C-A / a = C + A-B / b = a + B-C / C, and finding the fraction {a + B} {B + C} {C + a] / ab


Let B + C-A / a = C + A-B / b = a + B-C / C = k, then
b+c-a=ak b+c=(1+k)a (1)
c+a-b=bk c+a=(1+k)b (2)
a+b-c=ck a+b=(1+k)c (3)
(1) + (2) + (3) get (left plus left, right plus right)
2a+2b+2c=(1+k)(a+b+c)
∵ ABC are all nonzero natural numbers
∴a+b+c≠0
That is, 2 (a + B + C) = (a + B + C) (1 + k) 2 = 1 + k = 1
So B + C = 2A, C + a = 2B, a + B = 2C
{a+b}{b+c}{c+a]/abc
=2c×2a×2b/abc
=8



If ABC is three natural numbers greater than zero and a > B > C, then a > 1 (2) B-C a > 1 (3) B × C a < 1 (4)
(4) B < 1 of a + C, the correct of these four formulas is () (write the formula, fill in the serial number)


The correct one is that (3) satisfies the general formula and definitely satisfies the special situation
We can use the special value substitution method. Let a, B and C be 3, 2 and 1 respectively
(1)2/3



Let ABC be a non-zero natural number, and find out: a of | a | points plus B of | B | points plus C of | C | points


Because | a | = ± a, so: | a |, a = A / ± a = ± 1, similarly, we can get | B |, B = ± 1, | C |, C = ± 1. Classification discussion: the first case: when all three values are positive, the original formula = 1 + 1 + 1 = 3; the second case: when only two of the three values are positive, the original formula = 1 + 1-1 = 1; the third case: when the three values are only



If there are three natural numbers a, B and C, a × B = 6, B × C = 15 and a × C = 10, then a × B × C=______ .


Because 6 = 2 × 3, 15 = 3 × 5, 10 = 2 × 5, so a = 2, B = 3, C = 5, so a × B × C = 2 × 3 × 5 = 30



a. B. C is three natural numbers, a + B + C = 19. What is the maximum product of ABC?
fast


6+6+7=19
6*6*7=252



Known: A, B, C, D are natural numbers, a ^ 6 = B ^ 4, C ^ 3 = D ^ 2, a-c = 19, find the value of: b-d


Because a ^ 6 = B ^ 4, so a ^ 3 = B ^ 2, so a is a square number, otherwise, for any prime P, if p ^ (2k-1) | a, P ^ 2K does not divide a, then p ^ (6k-3) | a ^ 3 = B ^ 2, so p ^ (6k-2) | B ^ 2 = a ^ 3, so p ^ 2K | a, contradictory. And because C ^ 3 = D ^ 2, similarly, C is a square number