ABCDE has five numbers, among which a is larger than B, C is larger than D, but smaller than e, D is larger than B, and E is smaller than A. These five numbers are arranged from small to large

Bdcea

6 divided by () is equal to 24 of () is equal to 24 of () is equal to (): 4 is equal to 0.75 is equal to () 100 of

6 divided by (8) equal to (18) of 24 equal to (32) of 24 equal to (3): 4 equal to 0.75 equal to (75) of 100

ABCDE multiplied by 4 equals edcba, how much is ABCDE?

Man. I figured it out
In fact, they have a lot of rules
The result is: 21978 * 4 = 87912
My analysis is as follows:
The four bits of E * are a
A * 4 plus carry is e
That is to say, e should be a multiple of 4 plus a number
Use this conclusion in turn... To get the answer

ABCDE multiplied by 4 equals edcab, and each word represents a number to make the equation true

ABCDE 1) × 4 = edcba 2) five digit × 4 = five digit, so ten thousand bits have no carry, a = 1 or 2 because the individual bit of 2) is a, so a = 2; e can only be 3 or 8, and because a of 1) is 2, the first of 2) is e, so e = 8; 4 × 2 = 8, so thousand bits have no carry to ten thousand bits, B = 0 or 1 or 2, 8 × 4 to ten bits

ABCDE multiplied by 3 equals edcba, so the natural numbers of ABCDE are?

It doesn't exist

ABCDE multiplied by 3 equals edcba, so which natural numbers are ABCDE?

We can use the method of disproportion, ABCDE takes any natural number from 1 to 9, the original formula is impossible to hold
1. After multiplication, the number of digits remains unchanged, and the highest a can only be 1, 2 and 3
2. If a is 1, to make e * 3 get 1, e = 7; but the highest order 1 * 3 = 3, and finally get 7, b * 3 plus the following carry need to go to the highest order to get 4, which is impossible, because it can only get 2 at most
3. If a = 2, then E = 4, but the highest bit 2 * 3 = 6 > 4, there is a contradiction
4. If a = 3, e can only be equal to 1 (only 1 * 3 can produce 3), but there is still a contradiction in the highest order: 3 * 3 > 1

ABCDE multiplied by four equals edcba

A——E：21978
The reasoning is as follows:
Because the result is still 5 bits, a is less than or equal to 2
Because the result of E * 4 cannot be odd, a is not equal to 1, a = 2
Because a is equal to 2, only when e is equal to 8 can e × 4 = x2 be equal to or greater than 8
Because e = 8, B is less than 2
.

If five numbers are known to be ABCDE multiplied by one number (not equal to 1), the result is edcba, and ABCDE is calculated

87912

1.2.3.4.5.6.7.8.8 fill in two small circles respectively, so that the sum of four numbers in each big circle is equal to 21

8265
eight thousand seven hundred and thirty-three
four thousand seven hundred and forty-six
two thousand five hundred and eighty-six

Fill the eight numbers 1-8 in the small circle so that the sum of the five numbers on each circle equals 21
Two circles intersect and two numbers are shared.

1,8,6
2,4
3,5,7

ABCDE has five numbers, among which a is larger than B, C is larger than D, but smaller than e, D is larger than B, and E is smaller than A. These five numbers are arranged from small to large