Pig man and spider man start from 1 and count in turn. Each of them can only count one or two at a time. Who will report 30 first will win______ The announcer has a way to win

Pig man and spider man start from 1 and count in turn. Each of them can only count one or two at a time. Who will report 30 first will win______ The announcer has a way to win

If the pig man wants to win, let the spider man report the number first. If the spider man reports one, the pig man reports two; if the spider man reports two, the pig man reports one. Then the two people will report three numbers, that is, the pig man always reports a multiple of three. In this way, the final number reported by the spider man must be "28" or "28, 29", then the pig man can win The winning strategy is: first, let the opponent report first; second, the opponent report a number, you report two numbers, the opponent report two numbers, you report one number, always make the number you report is a multiple of three, such as three, fifteen, twenty-seven, etc

Pig man and spider man start from 1 and count in turn. Each of them can only count one or two at a time. Who will report 30 first will win______ The announcer has a way to win

If pig man wants to win, let spider man report the number first. If spider man reports one, pig man will report two; if spider man reports two, pig man will report one. Then they will report three numbers, that is, pig man always reports a multiple of 3. In this way, the final number reported by spider man must be "28" or "28, 29", then pig man will win The winning strategy is: first, let the opponent report first; second, the opponent report a number, you report two numbers, the opponent report two numbers, you report one number, always make the number you report is a multiple of three, such as three, fifteen, twenty-seven, etc

Two people count, 1 to 100, you can report 3 of 1, who report 100 to win, how to report I can win, why?
Explain why

You can report 3 of 1? 1 to 3? As long as you don't report 97

Two people take turns to report the numbers from one to the next. Each time you can report one, two or three numbers. The one who reports 60 first wins. Do you know the winning strategy?

So the winning strategy is: start from the other side, report the integer multiple of 4 every time, 4N

It consists of numbers 1, 2, 3, 4, 5 and 6, which are four digits without repetition. Arrange them in a column from small to large. What is the number 2315 in this column

A:
The first four digits of 1 are: 5 * 4 * 3 = 60. Then the 61st digit is 2134
The first four digits of 21 are 4 * 3 = 12. Then the number 60 + 12 + 1 = 73 is 2314
2315 is the 74th number

How many three digits can be made up of the numbers 0, 1, 2, 3 and 4? (the numbers on each digit can be repeated)

There are only three choices;
There are four choices for the other positions;
So number = 3 × 4 × 4 = 48 species;
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In a four digit number composed of six digits 0, 1, 2, 3, 4 and 5, if the number can be repeated, the number containing odd ones will be shared______ One

From the meaning of the question, we can know that this question is a classification and counting problem. The number contains odd 1, including two cases. One is that there is a 1, the other is that there are three 1. When the number has a 1, when 1 is in the first place and not in the first place, there are 53 + 4 × 3 × 5 × 5 = 425. When the number has three 1, there are 5 × 3 + 4 = 19. To sum up, there are 425 + 19 = 444, so the answer is: 444

Use & nbsp; 1, 0, 3, 5 & nbsp; to form () three digit numbers without repetition
A. 24B. 8C. 18D. 12

According to the analysis, there are 3 × 3 × 2 = 18 species. A: use 1, 0, 3, 5 to form 18 three digit numbers without repetition

If the single digit is 1, and there are exactly three four digits with the same number, it is called "good number", then the four digits with repeated numbers composed of 1, 2, 3 and 4 digits
How many good numbers are there?

2111,3111,4111
1211,1311,1411
1121,1131,1141
2221,3331,4441
12

A five digit number is composed of 0.1.2.3.4 (without repetition). How many five digits are there?

Because zero can't be in the first place, you can choose any one from 1.2.3.4. The last four digits are arranged in 4! = 24. 24 * 4 = 96, a total of 96 kinds