The supermarket sold 24 kinds of a drinks and 36 kinds of B drinks today. The simplest integer ratio of a drinks is () and the ratio is () to sell

The supermarket sold 24 kinds of a drinks and 36 kinds of B drinks today. The simplest integer ratio of a drinks is () and the ratio is () to sell

The supermarket sold 24 kinds of a drinks and 36 kinds of B drinks today. The simplest integer ratio of a drinks is (2:3), and the ratio is (2 / 3)

A bottle of 2.4 liters of beverage. He drank 2 / 5 of it yesterday and 3 / 5 of it today. How many liters are there in the bottle?

After drinking 2 / 5, there are 3 / 5 left, that is 2.4 * 3 / 5 = 1.44
Drink 3 / 5 liters today, that is 1.44-3 / 5 = 0.84 liters

Lili bought two bottles of the same beverage from supermarket a, which cost a total of 12 yuan. (1) if she bought six bottles of the same beverage, how much would it cost? (2) a week later, supermarket a held a sales promotion. If Lili needed six more bottles of the same beverage, how much would she charge now? How much would each bottle be cheaper than before

(1) 6 divided by 2 = 3 3 times 12 = 36 (yuan) a: it costs 36 yuan. (2) 36-12 divided by 2 = 30 (yuan) 30 divided by 6 = 5 (yuan) 12 divided by 2 = 6 (yuan) 6-5 = 1 (yuan) a: now it costs 30 yuan, and each bottle is 1 yuan cheaper than before

As shown in the figure is a service product launched by a cold drink shop: the store provides customers with a juice drink with a density of 950kg / m3, and ice is put in the drink. It is known that the mass of the drink is 0.6kg, the mass of the ice is 20g, the inner bottom area of the cup is 50cm2, and the depth of the drink in the cup is 10cm. What is the total pressure of the drink and ice on the bottom of the cup? （g=10N/Kg）

Pressure on the bottom of the cup: P = ρ GH = 950kg / m3 × 10N / kg × 0.1M = 950pa; pressure on the bottom of the cup: F = PS = 950pa × 50 × 10-4m2 = 4.75n. A: the total pressure on the bottom of the cup is 4.75n

How to write the English words of Hamburg?

hamburger

Xiao Ming has two pieces of 1 yuan, 2 yuan, 5 yuan and 10 yuan each. He wants to buy a hamburger. How can he pay 12 yuan for a hamburger without change
1.1 sheet 2 yuan 1 sheet 10 yuan 2.1 sheet 2 yuan 2 sheets 5 yuan 3.2 sheet 1 yuan 1 sheet 10 yuan 4 sheet 2 sheet 1 yuan 2 sheets 10 yuan what is method 5

There is a problem with the topic. Method 4 is equal to 22 yuan. 1) there must not be 10 yuan. There are two methods of 10 yuan. 2) there can only be one 5 yuan at most (if I think correctly, method 4 should be 2 1 yuan and 2 5 yuan). 3) but if there is only 1 5 yuan, add 2 1 yuan and 2 2 2 yuan, and it's only 11 yuan. 4) it's only to wait for the hamburger discount or buy 2 hamburgers and sell them to others

10 yuan, 5 yuan, 2 yuan, how to pay 18 yuan without change
Except 10 + 5 + 2 + 1

1+2+5+10

There are 1 1 yuan note, 2 2 yuan notes, 1 5 yuan note and 1 10 yuan note. You can pay several different currency values without change

1 = 1; 2 = 2; 3 = 1 + 2; 4 = 2 + 2; 5 = 5; 6 = 1 + 5; 7 = 2 + 5; 8 = 1 + 2 + 5; 9 = 2 + 2 + 5; 10 = 10; 11 = 1 + 10; 12 = 2 + 10; 13 = 1 + 2 + 10; 14 = 2 + 2 + 10; 15 = 5 + 10; 16 = 1 + 5 + 10; 17 = 2 + 5 + 10; 18 = 1 + 2 + 5 + 10; 19 = 2 + 2 + 5 + 10; 20 = 1 + 2 + 2 + 5 + 10

There are enough 1 yuan, 2 yuan and 5 yuan at present. How many kinds of goods with different unit prices can you buy if you can use up to 4 pieces? (no change after payment)
If I have a good answer, I'll add another 50 points!

It's still difficult

Xiaoying wants to go to the supermarket. In order not to produce change less than 10 yuan, she has to bring at least 5 yuan, 2 yuan, 1 yuan notes, a total of () pieces?
a,3 b,4 c,5 d,6

B one 5 yuan. Two 2 yuan. One 1 yuan. 1:1 yuan; 2:2 yuan; 3:2 + 14:2 + 25:56:5 + 17:5 + 28:5 + 2 + 19:5 + 2 + 2