The following figure is a schematic diagram of a beverage bottle. The volume of the beverage bottle is 1250 ml, which contains some drinks. When the bottle is placed upright, the beverage is% 0

The following figure is a schematic diagram of a beverage bottle. The volume of the beverage bottle is 1250 ml, which contains some drinks. When the bottle is placed upright, the beverage is% 0

Bottom area: 1250 ÷ (20 + 5) = 50 (cm2)
Drink in bottle: 50 × 20 = 1000 (ML)
A: the drink in the bottle is 1000 ml

A bottle of drink, the volume of the bottle is 625ml, Wang Li drank some, want to know how much is left, so Wang Li put the bottle, measure the height of the drink is 8cm, and then put the bottle upside down, measure the height of the spare part is 4.5cm (as shown in the figure), quickly calculate the result. Do you calculate the content of the drink in the bottle______ Ml

Suppose the bottom area of the bottle is x square centimeter, & nbsp; & nbsp; 8x = 625-4.5x, 12.5x = 625, & nbsp; & nbsp; & nbsp; X = 50, so the existing beverage in the bottle: 50 × 8 = 400 (ML), answer: the existing beverage in the bottle is 400 ml