A truck at 160 km / h drove from city a to city B at 9:00, and a bus at 232 km / h also drove from city a to city B at 11:00 City, in order to drive safely, the distance between trains should not be less than 8 kilometers, so when should the truck stop at the latest to let the bus miss? Step by step, don't write it briefly, it's very urgent

160 * (11-9) = 320 km
(160-8) / (232-160) = 19 / 9 = 2 and 1 / 9 hours
11 + 2 1 / 9 = 13 1 / 9 hours, that is 1 1 / 9 pm

Both passenger and freight cars drive from city a to city B at the same time. The speed of passenger cars is 90 kilometers per hour, and that of freight cars is 70 kilometers per hour. When the passenger cars arrive at city B, they return immediately and meet the freight cars 50 kilometers away from city B. how many kilometers is the distance between city a and city B?

At the time of meeting, there are more buses than trucks: 50 × 2 = 100 km
Meeting time: 100 ÷ (90-70) = 5 hours
Distance between a and B: 90 × 5-50 = 400 km

A passenger train with a speed of 45km / h will drive from station a to station B at 9am, and a freight train with a speed of 55km / h will also drive from station a to station B at 11am
In order to ensure traffic safety, it is stipulated that the distance between trains should not be less than 8 km. When is the latest time for a bus to stop and give way to a truck?

Make way for vehicle B after X hours at the latest
According to the meaning of the title: 55x-45 (x + 2) > = 8
10X>=98
10> = 9 and 4 / 5 hours
So the latest time can not be at 11 + 9 and 4 / 5 = 20:48

The speed of the bus is x km / h, and the speed of the truck is 70 km / h. The two cars start from city a to city B at the same time. After driving for 5 hours, the bus just arrives at city B, but the train has not yet arrived. At this time, the truck is thousands of meters away from city B?

At this time, the truck is 5 (X-70) = 5x-350 km away from city B

From Jiacheng to Yicheng, it takes 6 hours for trucks and 5 hours for buses. The speed of buses is () percent faster than that of trucks

(1/5-1/6)/(1/6)*100%=20%
"The speed of passenger cars is () percent faster than that of freight cars" is based on the speed of freight cars

It takes five hours for a bus to go from city a to city B, and six hours for a truck to go from city B to city A. write down the speed ratio of the bus to the truck and simplify it

The speed ratio of passenger cars and freight cars is 6:5

From city a to city B, buses travel 48 kilometers per hour and arrive in 5 hours
How many hours does it take for a truck to travel from city a to city B

Truck speed = 48 × (1 + 1 / 4) = 60 km / h
Need = 48 × 5 △ 60 = 4 hours

The distance between the two cities is 558 kilometers. The freight cars drive from city B to city a at the speed of 48 kilometers per hour. The passenger cars drive from city a to city B only 2 hours after the freight cars leave

The distance between the two cities is 558 km. The freight cars drive from city B to city a at the speed of 48 km per hour. The passenger cars drive from city a to city B only two hours after the freight cars drive. After another six hours, the speed of the passenger cars is calculated (equation)
Let the bus speed be x km / h
6（48+x)+48×2=558
6(48+x)=462
48+x=77
x=29

The distance between the two cities is 588 kilometers. The freight cars are driven from city B to city a at the speed of 48 kilometers per hour. The passenger cars are driven from city a to city B only 2 hours after the freight cars leave
After another six hours, the two cars met to find the speed of the bus

If the speed of the bus is x km / h, then
48×(2+6)＋6x=588
That is, 6x = 204
The solution is x = 34
Therefore, the speed of the bus is 34 km / h

From city a to city B, it takes five hours for trucks and six hours for buses. What is the simplest ratio between the speed of trucks and that of buses______ ．

The speed of freight car: 1 △ 5 = 15, the speed of passenger car: 1 △ 6 = 16, the speed ratio of freight car and passenger car: 15:16 = 6:5. A: the speed ratio of freight car and passenger car is 6:5