There are 540 kilometers from a to B. a car has been driving 60 kilometers per hour from a to B for two hours. How many hours will it take to reach B

There are 540 kilometers from a to B. a car has been driving 60 kilometers per hour from a to B for two hours. How many hours will it take to reach B

(540-60x2) / 60 = 7 hours

How many hours does it take for a car to complete the whole journey at this speed?

Suppose it takes x hours for the car to complete the whole journey
2∶140=x∶350
140x=350×2
x=700/140
x=5
It will take five hours for this car to complete the whole journey

The distance between a and B is 504km. A car drives from a to B in 6 hours, two-thirds of the whole journey. How many hours will it take to reach B at such a speed

6:2/3=x:1/3

The distance between the two cities is 660 km. A passenger train and a freight train leave the two cities at the same time. After 4 hours, they meet. It is known that the speed of the passenger train is 1.2 times that of the freight train. How many kilometers more does the passenger train travel per hour than the freight train?

The speed of freight car is set at XKM / h
Then the bus speed is 1.2xkm/h
4(1.2x+x)=660
x=75
1.2x=90
90-75=15
A: buses travel 15 kilometers per hour more than trucks

The distance between the two cities is 380 km. A passenger train and a freight train leave the two cities at the same time and meet after 4 hours. It is known that the speed ratio of the passenger train and the freight train is 11:8. How many kilometers more does the passenger train travel per hour than the freight train?

Speed sum of passenger car and freight car: 380 △ 4 = 95 (km), speed of passenger car: 95 × 1111 + 8 = 55 (km), speed of freight car: 95 × 811 + 8 = 40 (km), more passenger car per hour than freight car per hour: 55-40 = 15 (km); the comprehensive formula is: 380 △ 4 × [11 (11 + 8) - 8 (11 + 8)] = 95 × 319 = 15 (km). Answer: passenger car travels 15 km more per hour than freight car

The railway between a and B is 702km long. A passenger train and a freight train leave from the two places at the same time. The passenger train runs 24km per hour. The speed of the freight train is 1 / 6 faster than that of the passenger train. The two trains meet a few hours after they leave

24x（1+1/6)=28
702÷（24+28）=13.5
The two cars met 13.5 hours after they left

The railway between Party A and Party B is 250 km long. A freight train and a passenger train leave from both places at the same time. They meet 1.25 hours later, and the passenger train runs 107 km per hour
I want to write a complete book,

Freight car speed
250÷1.25-107
=200-107
=93 km / h

The railway between station a and station B is 460 km long. A passenger train and a freight train leave from station a and station B at the same time,
It is known that the speed of a passenger car is 60 kilometers per hour, and that of a freight car is 11 / 12 of that of a passenger car?

Truck speed = 60 × 11 / 12 = 55 km / h
Encounter = 460 (60 + 55) = 4 hours

The length of the railway between a and B is 693 km. A passenger train and a freight train leave at 9 a.m. from the two places at the same time. The passenger train runs 70 km per hour and the freight train 56 km per hour. After a few hours, the two trains meet?

693 (70 + 56), = 693 (126), = 5.5 (hours). A: after 5.5 hours, the two trains meet

The distance between a and B is 540 km. The speed ratio of freight train and passenger train is 4:5, and the speed ratio of freight train and passenger train is 4:5
It's thousands of meters

Speed sum: 540 △ 5 = 108 (km / h)
Truck speed: 108x4 / (4 + 5) = 48 (km / h)
Bus speed: 108-48 = 60 (km / h)