Ming and Qiang start from a and B at the same time, and meet at 1200 meters from the end. It is known that Xiaoqiang's speed is three eighths of Xiaoming's speed, so we can find the distance

Ming and Qiang start from a and B at the same time, and meet at 1200 meters from the end. It is known that Xiaoqiang's speed is three eighths of Xiaoming's speed, so we can find the distance

It should be: the midpoint
1200 × 2 = 2400m
1－3/8＝5/8
2400 △ 5 / 8 = 3840m
3840 × (1 + 3 / 8) = 5280m

A and B go from a to B at the same time. A rides a bicycle and B rides a motorcycle. B is 24km faster than a per hour. A spends 3 / 4 more time than B. what's the speed of a

A uses 3 / 4 more time than B, that is, a uses 1 + 3 / 4 = 7 / 4 of B. his speed is only 1 / 7 / 4 = 4 / 7 of B, 1-4 / 7 = 3 / 7 less than B, B's speed is 24 / 3 / 7 = 56 km, a's speed is 56-24 = 32 km per hour