From station a to station B, it takes 7 hours for car a and 7 hours and 30 minutes for car B. car a is 4 kilometers faster than car B. find the distance between station a and station B and the speed of car a and station B

From station a to station B, it takes 7 hours for car a and 7 hours and 30 minutes for car B. car a is 4 kilometers faster than car B. find the distance between station a and station B and the speed of car a and station B

The distance between the two stations is x km
X/7-X/7.5=4
7.5X-7X=4*7*7.5
0.5X=210
X=420
The distance between the two stations is 420 km
A speed = 420 / 7 = 60 km / h
B speed = 420 / 7.5 = 56 km / h

A and B are traveling from ab at different speeds at the same time. On the way, they meet for the first time, 60 kilometers away from A. after meeting, they continue to travel at the same speed
Speed forward. After arriving at the destination, the two cars immediately return. On the way, they meet for the second time. This is 40 kilometers away from A. how many kilometers away is the first meeting point from B?

Let AB distance be s,
V a T1 + V B T1 = s
V a (T1 + T2) + V B (T1 + T2) = 3S
It is concluded that T2 = 2t1
60 + V, T1 = s
V b T2 = 60 + 40
S = 110km
The distance between the first meeting point and B
110-60=50km
I don't understand. I can draw a picture