A car travels 50 kilometers per hour, B car travels 40 kilometers per hour. Both a and B cars drive from a to B at the same time. On the way, a car breaks down After parking for 2 hours, continue to move forward, and arrive at B at the same time. Find the distance between a and B? Do not use the equation, and list the formula and meaning

A car travels 50 kilometers per hour, B car travels 40 kilometers per hour. Both a and B cars drive from a to B at the same time. On the way, a car breaks down After parking for 2 hours, continue to move forward, and arrive at B at the same time. Find the distance between a and B? Do not use the equation, and list the formula and meaning

Car a travels 10 kilometers more per hour than car B
Car a stopped for 2 hours, and car B walked 40 × 2 = 80 km in these two hours
In other words, a car to 80 / 10 = 8 hours to accumulate 80 km advantage
Therefore, car a has been driving for 8 + 2 = 10 hours (2 hours in the middle) and car B has been driving for 10 hours
So the distance between a and B is 40 × 10 = 400 km

Car a and car B leave each other from a and B. car a travels 35 kilometers per hour and car B 40 kilometers per hour. When car a finishes 7 / 20 of the whole journey, it meets car B. at this time, car B travels 120 kilometers more than car a?

When we meet,
Car B runs the whole journey 1-7 / 20 = 13 / 20
The whole course is: 120 △ 13 / 20-7 / 20 = 400 km
Vehicle a: 400 × 7 / 20 = 140 km
Time: 140 △ 35 = 4 hours
Vehicle B: 400 × 13 / 20 = 260 km
Time: 260 △ 40 = 6.5 hours
So B starts first, starts first: 6.5-4 = 2.5 hours

A and B start from ab at the same time and travel in opposite directions. Moreover, the speed of car a is 1 / 5 faster than that of car B. when they meet, car a is still 80 kilometers away from B. how many kilometers are there between AB and B?

(1 + 5): 1 = (6 out of 5 × 5): (1 × 5)
=6：5
80 divided by 5 / 11 = 176 (km)

A and B drive from a to B, a's speed is 40 km / h, B's speed is 50 km / h, a starts for half an hour, two cars arrive at B at the same time, find the distance between a and B

Suppose B leaves x hours later and the two cars meet, then a takes x + 0.5 hours
40（X+0.5）=50X
X=2
Distance = speed x time = 50x2 = 100km