Car a and car B leave 360km at the same time and meet each other in 5 hours. Car a travels x km per hour and car B 40km per hour Finding the equating relation and equation

Car a and car B leave 360km at the same time and meet each other in 5 hours. Car a travels x km per hour and car B 40km per hour Finding the equating relation and equation

Speed and time of encounter = distance
5（x+40）=360
x+40=72
x=32
answer

Car a and car B leave from two places at the same time and meet each other in five hours. The distance between the two places is 360km. Car B travels 40km per hour?

(360-40*5)/5=32
This is best understood, a total of 360, a car walked 5 hours, the rest is another car's journey, and then divided by 5

1. Party A and Party B depart from two places 360km apart at the same time, and meet each other in 5 hours. Car a travels x km per hour and car B 40 km per hour
Equivalent relation ()
Equation ()
2. A piece of iron wire can be made into a square with a side length of 25cm. Now it is changed into a rectangle with a length of xcm and a width of 15cm
Equivalent relation ()
Equation ()

2. A piece of wire can be made into a square with side length of 25cm, now it is changed into a square with side length of 25cm

After 6.5 hours, the two vehicles meet. It is known that the distance between the two places is 572 kilometers. How many kilometers does vehicle a travel per hour and vehicle B travel per hour?

B. every hour:
572 △ 6.5-40 = 48 km