The passenger car and the freight car leave from a and B at the same time. The passenger car runs 50km per hour, and the speed of the freight car is 80% of that of the passenger car. After meeting, the passenger car continues to travel for 3.2 hours to reach B. how many kilometers are there between a and B?

The passenger car and the freight car leave from a and B at the same time. The passenger car runs 50km per hour, and the speed of the freight car is 80% of that of the passenger car. After meeting, the passenger car continues to travel for 3.2 hours to reach B. how many kilometers are there between a and B?

(50 × 3.2) △ (50 × 80%) = 160 △ 40 = 4 (hours) (50 + 50 × 80%) × 4 = (50 + 40) × 4 = 90 × 4 = 360 (kilometers) answer: A and B are 360 kilometers apart

A and B set out from place a to place B 26km away at the same time. A rides a bicycle and B walks. It is known that a's speed is 1km / h faster than twice that of B. after a arrives at place B, he immediately returns from place B. on the way, he meets B. The time from their departure is 4 hours. Q: what are their respective speeds? How far is the meeting point from place B?

Let B's speed be x km / h and a's speed be (2x + 1) km / h;
[（2x+1）+x]*4=2*26
The solution is x = 4km / h
Speed of a = 2x + 1 = 9km / h
The distance between the meeting point and B is s = 26-4 * 4 = 10km
Thank you