The first time they met at a distance of 90 km from city a, the two cars continued to drive at the same speed and returned to the same road after arriving at the station. How many kilometers was the distance between station a and station B when they met for the second time?

The first time they met at a distance of 90 km from city a, the two cars continued to drive at the same speed and returned to the same road after arriving at the station. How many kilometers was the distance between station a and station B when they met for the second time?

The first time they met at a distance of 90 km from city a, the two cars continued to drive at the same speed and returned to the same road after arriving at the station. The second time they met at a distance of 50 km from city B, what is the distance between station a and station B?
90 × 3-50 = 230 km

A and B drive from the East and west at the same time. Car a runs 56 kilometers per hour, while car B runs 48 kilometers per hour. The two cars meet at 32 kilometers away from the midpoint. The distance between the East and the west is several thousand meters,

When the two cars meet at 32 km from the midpoint, it means that car a exceeds 32 km from the midpoint and car B is 32 km from the midpoint. That is to say, car a travels 32 * 2 = 64 km more than car B when they meet
One hour for car a is 56-48 km more than one hour for car B. how many hours is 64 km more? 64 / 8 = 8 hours
Find the distance (56 + 48) * 8 = 832km

A, B and C go from a to B at the same time. A travels 6 kilometers more than B per hour by bike, 7 and 1 / 2 kilometers more than C. after arriving at B in 3.5 hours, a immediately returns along the original road and meets B 15 kilometers away from B. question: (1) what's the distance between a and B? (2) how long has C been meeting a?

(1) When a returns, he meets B 15 kilometers away from B, which means that a has traveled two more 15 kilometers than B (15 kilometers when he arrives at B + 15 kilometers when he returns), a total of 30 kilometers. When a travels 6 kilometers per hour, it means that a has walked 30 / 6 = 5 hours. Then he arrives at B in 3.5 hours. When he returns to a, he has walked 5-3.5 = 1.5 hours
He walks 15 kilometers in 1.5 hours, and the speed of Najia is: 15 / 1.5 = 10 kilometers / hour
He walked 3.5 hours from a to B. the distance between a and B is 3.5 * 10 = 35 km
(2) It is known that a travels 7.5km more per hour than C. The first question about a's speed is known,
The speed of C is: 10-7.5 = 2.5km/h
When a arrives at B, the distance is 2.5 * 3.5 = 8.75 km
The total distance is 35-8.75 = 26.25 km
The speed sum of the two is 2.5 + 10 = 12.5kph
Therefore, the time required after 3.5 hours is 26.25 / 12.5 = 2.1 hours
The total time is 3.5 + 2.1 = 4.6 hours

It's an 800 meter long circular track. A and B run from the same starting point, in the same direction and at the same time. A's speed is 320 m / min. B's speed is 280 M / min. Q: they will meet in a few minutes

Suppose the distance a runs is x, we can make a table: time distance speed A: () XM 320m / min B: () () 280m / min