Party A and Party B are going on the same road at the same time. Party A travels 3 kilometers per hour and Party B 5 kilometers per hour. Party A passes by place a at 12 noon and asks Party B what time in the afternoon

Party A and Party B are going on the same road at the same time. Party A travels 3 kilometers per hour and Party B 5 kilometers per hour. Party A passes by place a at 12 noon and asks Party B what time in the afternoon

1. If the conditions are not complete, it is impossible to calculate. 2. Let a's speed be V1 and B's speed be v2519 = (V1 + V2) * 5.2519-v2 * 2 = (V1 + V2) * 4. Solve the binary linear equations by yourself. 3. If there is a problem in writing, it should be asking when a can meet B. if the distance between AB and B is s, then VA = s / 2, VB = s / 3T = s / (VA + VB) remember

A and B go along a road from west to East. A travels 3 kilometers per hour, b 5 kilometers per hour. A passes by a at 12 noon, B passes by a at 2 pm
(even above)
After a, how far does B catch up with a?
(solved by equation)
Good answer, 30 more points!

There are two hours between 12 noon and 2 pm
At 2pm, a is 3 * 2 = 6km away from a
Let B catch up with Jiali a by X kilometers
X/5=(X-6)/3
X=15
B overtakes Jiali a by 15 kilometers

The speed of a is 6 m / s, and that of B is 4 m / s. After a few laps, can a surpass B by one lap?

400 × 2 ÷ (6-4) × 4 ／ 400 = 800 ／ 2 × 4 ／ 400, = 4 (LAPS). A: after 4 laps of B, a can surpass B by one lap

The speed of a is 6 m / s, and that of B is 4 m / s. After a few laps, can a surpass B by one lap?

400 × 2 ÷ (6-4) × 4 ／ 400 = 800 ／ 2 × 4 ／ 400, = 4 (LAPS). A: after 4 laps of B, a can surpass B by one lap