The two trains leave 570 kilometers apart at the same time. Car a travels 110 kilometers per hour, car B 80 kilometers per hour. After a few hours, the two trains meet?

The two trains leave 570 kilometers apart at the same time. Car a travels 110 kilometers per hour, car B 80 kilometers per hour. After a few hours, the two trains meet?

570 / (110 + 80) = 570 / 190 = 3 hours

The two trains leave from two places 570 kilometers apart. Car a travels 110 kilometers per hour, and car B travels 80 kilometers per hour. After several hours, the two trains meet. The two trains are solved by two methods of equation calculation

570 / (110 + 80) = 3 hours
Let the solution meet after y hours
(110+80)y=570
190y=570
y=3
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The two trains leave at the same time from two places 570 kilometers apart. Car a travels 110 kilometers per hour, and car B travels 80 kilometers per hour
There are two methods, one I know is the simplest 80x + 110x = 570km, the other is what, fast, fast, offering a reward of 100 points!

570÷（110+80）
=570÷190
=3 hours

The two trains leave from a and B at the same time. It takes 20 hours for the express train to complete the whole journey and 30 hours for the local train to complete the whole journey. The two trains meet 15 hours after departure. It is known that the express train stops for 4 hours and the local train stops for several hours?

First, take the distance between a and B as a whole "1", then the speed of express train is 120, the speed of local train is 130, the distance of a line when meeting: 120 × (15-4) = 1120, the distance of B line when meeting: 1-1120 = 920, the time of B line when meeting: 920 △ 130 = 13.5 (hours), the time of local train stop: 15-13.5 = 1.5 (hours), a: the local train stayed for 1.5 hours in the future of meeting