A and B leave AB at the same time. A returns to B immediately after arriving at B. when it is 45 km away from B, it meets B. the speed ratio of a and B is 3:2. What is the distance a takes? It's a process

A and B leave AB at the same time. A returns to B immediately after arriving at B. when it is 45 km away from B, it meets B. the speed ratio of a and B is 3:2. What is the distance a takes? It's a process

If the distance between a and B is x km, then
（x+45）:(x-45)=3:2
The solution is x = 225
The distance a takes is 225 + 45 = 270 km

A and B depart from AB and run in opposite directions. 45 minutes later, they meet at a distance of 9 km from the midpoint. It is known that the speed of a is 1.5 times that of B
How many kilometers did the two cars travel when they met?

A 9 × 2 × 1.5 / (1.5-1) = 54 km
B 9 × 2 / (1.5-1) = 36 km

A and B start from ab at the same time and face each other. They meet 45 kilometers away from the midpoint of the two places. It is known that the speed of a is 1.2 times that of B. the distance between AB and B is calculated

Distance difference between two vehicles = 45 * 2 = 90 km
Whole course = 90 △ 1.2-1 × (1.2 + 1) = 990 km

It takes 12 hours for car a to go from tunnel a to place B, and 15 hours for car B to go from place B to place a?

A / b speed ratio 15:12 = 5:4
A takes 5 / (5 + 4) = 5 / 9 of the whole journey
The distance between the two places is 45 △ 5 / 9-1 / 2 = 45 △ 1 / 18 = 810km