13. A and B two cars respectively from AB two places at the same time, the first meeting 80 km away from a, after meeting the two cars continue to drive, respectively to Ba immediately return, and 40 km away from B at the second meeting. Find the distance between AB two places

13. A and B two cars respectively from AB two places at the same time, the first meeting 80 km away from a, after meeting the two cars continue to drive, respectively to Ba immediately return, and 40 km away from B at the second meeting. Find the distance between AB two places

The first time they met, the two cars traveled a distance of AB, and car a traveled 80 kilometers
When they first met, the two cars traveled together for three AB distances, so car a traveled 80 × 3 = 240 km
We also know that when we met for the second time, car a traveled 40 kilometers more than an ab
So the distance between AB and ab is 240-40 = 200 km
The comprehensive formula is as follows:
80 × 3-40 = 200 km
Have a good time

A and B are facing each other from a and B. for the first time, they meet at a distance of 80 km from A. they continue to drive back to two places and meet at a distance of 40 km from B

(2s-40)/(s+40)=(s-80)/80
S is the distance equal sign, and both sides are the velocity ratio of B and a
This problem to default speed unchanged, reverse, etc. do not delay time, or there will be no solution
The level of the author is too low
S = 200km

Train a and B depart from a and B at the same time, and meet 75 km away from a for the first time,
After arriving at the destination, they return immediately. The second meeting is 55 kilometers away from B. find the distance between a and B

In the first encounter, the two cars completed one journey together, and in the second encounter, the two cars completed two journeys together, each driving twice as much as the first
The first encounter a walked 75 km, the second encounter a walked 2 * 75 = 150 km, from the start to the second encounter a total of a whole journey and 55 km, that is, a whole journey and 55 km = 75 + 150 = 225, so the distance between the two places is 225-55 = 170 km

A and B trains depart from ab at the same time. For the first time, they meet 50 kilometers away from A. after meeting, they continue to move forward and return immediately after reaching the destination. For the second time, they meet 26 meters away from B?
26km

I calculate by 26 kilometers
50×3-26=124km