A. B is 80km away. A and B start from a to B. one hour after a starts, B catches up with a speed 1.5 times that of A. when B catches up with B, a arrives 20 minutes ahead of B. what's the speed of a and B?

A. B is 80km away. A and B start from a to B. one hour after a starts, B catches up with a speed 1.5 times that of A. when B catches up with B, a arrives 20 minutes ahead of B. what's the speed of a and B?

Suppose the speed of a is XKM / h, then the speed of B is 1.5xkm/h. According to the meaning of the question, we can get: 80x − 801.5x = 1 − 2060 solution: x = 40 test: substitute x = 40 into 3x ≠ 0, so x = 40 is the solution of the original equation, so the speed of B is: 1.5x = 60 (km / h) answer: the speed of a and B is 40km / h and 60km / h respectively

A and B are 80 kilometers apart. One hour after car a starts from a, car B starts from a, catching up at 1.5 times the speed of car A. when car B arrives at B, car a starts first

Original title:
A and B are 80 kilometers apart. One hour after a car starts from a, B also starts from a, catching up with a at 1.5 times of a's speed. When B arrives at B, a has arrived at B 20 minutes earlier than B to find the speed of a and B
Let a speed be x km / h and B speed be 1.5 x km / h
80/x-1-80/(1.5x)=-1/3
80/x-160/(3x)=2/3
240-160=2x
The solution is x = 40
40×1.5=60
So the speed of a is 40 km / h and that of B is 60 km / h

A. B is 80km away. A and B start from a to B. one hour after a starts, B catches up with a speed 1.5 times that of A. when B catches up with B, a arrives 20 minutes ahead of B. what's the speed of a and B?

Suppose the speed of a is XKM / h, then the speed of B is 1.5xkm/h. According to the meaning of the question, we can get: 80x − 801.5x = 1 − 2060 solution: x = 40 test: substitute x = 40 into 3x ≠ 0, so x = 40 is the solution of the original equation, so the speed of B is: 1.5x = 60 (km / h) answer: the speed of a and B is 40km / h and 60km / h respectively

A and B go from a to B at the same speed. A goes 12 kilometers before B starts. When B arrives at B, they return at the same distance
We can't use equation, we need formula

A and B go from a to B at the same speed. A goes 12 kilometers before B starts. After arriving at B, B immediately returns and meets B at a quarter of the distance from B (1 / 4 from B to a). How many kilometers is the distance between a and B? If the two cars have the same speed, a travels 12 kilometers more than B when they meet