A and B both go from a to B. A goes 80 meters per minute to catch up with B. It is known that B goes 65 meters per minute. A takes 20 minutes to catch up with B. how many meters does B start before a? Use X to solve the equation?

A and B both go from a to B. A goes 80 meters per minute to catch up with B. It is known that B goes 65 meters per minute. A takes 20 minutes to catch up with B. how many meters does B start before a? Use X to solve the equation?

Let's start x meters first
65·20+x=80·20
1300+x=1600
The solution is x = 300

A and B from a to B, a speed of 80 meters per minute to catch up with the first start of B, know B walk 65 meters per minute, a with 20 minutes to catch up, B than a

20 * (80-65) = 20 * 15 = 300m, that is, B starts 300m first

Party A and Party B go from a to B. Party B walks 65 meters per minute. After 300 meters, Party A starts. After 20 minutes, they catch up with Party B. they are in a hurry

Let a speed be x per minute
(x-65)*20=300
x-65=15
x=80
A: the speed of a is 80 meters per minute

The distance between a and B is 450 kilometers. A bus and a truck leave from a and B station at the same time. After 5 hours, the bus runs 43.2 kilometers per hour
How many kilometers does the truck travel per hour?

Examples of answers:
450÷5-43.2
=90-43.2
=46.8 km
Travel 46.8 kilometers per hour