At the same time, the passenger and freight cars drive in opposite shape from the midpoint of a and B. after 5 o'clock, the passenger cars arrive at a place, and the freight cars are 60 km away from B place. The speed ratio of the freight cars is 5:7, and the total distance is 60 km

At the same time, the passenger and freight cars drive in opposite shape from the midpoint of a and B. after 5 o'clock, the passenger cars arrive at a place, and the freight cars are 60 km away from B place. The speed ratio of the freight cars is 5:7, and the total distance is 60 km

Suppose the speed of freight car is 5 x km / h and that of passenger car is 7 x km / h
"A and B drive in opposite shape at the midpoint" indicates that the two vehicles have the same driving distance
7x * 5 = 5x * 5 + 60 gives x = 6
The bus speed is 7 * 6 = 42km / h
5 hours 42 * 5 = 210km
Distance between a and B = 210 * 2 = 420 km

The bus and the truck run in the opposite direction from the middle of a and B at the same time. After 5 hours, the bus arrives at a, and the truck is 60 kilometers away from B,
The ratio is 5:7. What's the distance between a and B

[analysis] the distance ratio of passenger car and freight car is equal to the speed ratio, so when the passenger car completes half of the whole journey, the freight car runs 5 / 7 × 2 of the whole journey (i.e. 5 / 14). The corresponding score of 60 km is (1 / 2-5 / 7 × 2)
60 (1 / 2-5 / 7 × 2) = 420 (km)
A: the distance between a and B is 420 kilometers

Five hours later, when the bus arrives at the place a, the truck is 60 kilometers away from the place B
The speed ratio of the bus is 5:7, and the distance between a and B is calculated

If the speed of passenger car and freight car is x and Y respectively, there will be
X：Y=7:5
5X+5Y+60=5X*2
The solution is x = 42, y = 30
The distance between the two places is L = 5x + 5Y + 60 = 420 km

A passenger car and a freight car run from a and B at the same time. They meet at a distance of 30 kilometers from the midpoint. It is known that the speed ratio of the passenger car and the freight car is 5:4. How many kilometers did the freight car travel when they meet?

When we met, the distance of the bus in the total length = 5 ^ (5 + 4) = 5 / 9, the total length = 30 ^ (5 / 9-1 / 2) = 30 ^ (1 / 18) = 540 km, the distance of the truck = 540 ^ (5 + 4) × 4 = 240 km. I'm glad to answer for you. I wish you progress in your study! 523 will always answer for you ~ ~ if you agree with my answer, please click