The two cars run from two places 360 kilometers apart at the same time and meet in four hours. How many kilometers per hour does a car run at 35 kilometers per hour? fast
Set B 1 hour x km
4x+4*35=360
4x=360-4*35
4x=220
x=55
A: B 55 kilometers per hour
At the same time, a and B are facing each other. When a is 20 kilometers away from the midpoint, they meet B again
B distance between the two places
Speed difference between two vehicles = 60-40 = 20 km / h
Distance difference between two cars = 20 + 20 = 40 km
Encounter time = 40 △ 20 = 2 hours
Distance between the two places = 2 * (60 + 40) = 200 km
A and B cars are running from AB to ab at the same time. A car travels 40 kilometers per hour, B car travels 60 kilometers per hour, and the two cars are 14.4 kilometers away from the midpoint
Meet. Find the distance between AB and two places
A is faster than B, so a is 14.4km above the midpoint, and B is 14.4km away from the midpoint
14.4x2 = 28.8 (km)
A has more lines per hour than B:
60-40 = 20 (km)
So the time of meeting is:
28.8 △ 20 = 1.44 (hours)
Therefore, the distance between the two places is:
(60 + 40) x1.44 = 144 (km)
The comprehensive formula is as follows:
14.4x2÷(60-40)x(60+40)
=28.8÷20x100
=1.44x100
=144 (km)
The speed of car a is 56 km / h, and that of car B is 48 km / h. The two cars are facing each other. Car B starts 1.5 hours ahead of time and meets at 26 km from the midpoint for the whole journey
Two cases: set the whole process as S
1、 If a reaches half the distance + 26 km, then:
(0.5S-1.5*48)/48=(0.5S+26)/56 S=1320
2、 If a walks half the way to - 26 km, then:
(0.5S-1.5*48+26)/48=(0.5S-26)/56 S=332