Car a and car B leave the two places at the same time along the highway. Car a travels 48 kilometers per hour on average, and car B 54 kilometers per hour on average. When they meet, they are 36 kilometers away from the midpoint of the two places. How many kilometers are there between the two places?

Car a and car B leave the two places at the same time along the highway. Car a travels 48 kilometers per hour on average, and car B 54 kilometers per hour on average. When they meet, they are 36 kilometers away from the midpoint of the two places. How many kilometers are there between the two places?

Driving time when meeting: 36 × 2 ^ (54-48), = 72 ^ 6, = 12 (hours); distance between the two places: (48 + 54) × 12, = 102 × 12, = 1224 (km); answer: the distance between the two places is 1224 km

Car a and car B start from A. B at the same time and travel in opposite directions. Car a travels 56 kilometers per hour and car B 40 kilometers per hour. When car B reaches 2 / 5 of the whole journey, car a has exceeded the midpoint of 12 kilometers. How many kilometers are there between A. B and car a?

The speed of car a is the same as that of car B
56÷40=7/5
B car line 2 / 5 at the same time, a car line
2/5×7/5=14/25
Therefore, the two places are far apart
12÷(14/25-1/2)
=12÷3/50
=12×50/3
=200 (km)

Car a travels 56 kilometers per hour, while car B travels 48 kilometers per hour. The two cars are facing each other at the same time. They meet at 32 kilometers from the midpoint to find the distance ab

Because they meet at 32km away from the midpoint, car a has passed 32km away from the midpoint, while car B is 32km away from the midpoint, so car a travels 64km more than car B, so the driving time is 64 (56-48) = 8 hours
The distance between the two places is (56 + 48) × 8 = 832km

Car a travels 56 kilometers per hour, and car B travels 48 kilometers per hour. The two cars are facing each other at the same time. They meet at 32 kilometers from the midpoint. Find the distance between ab

Let the distance of AB be X
The known quantity is used to express the time of meeting: X / (56 + 48) hours, and the distance from the midpoint is: X / 2km. Because a is fast, so a exceeds the midpoint, the equation can be listed as follows
56X/（56+48）-X/2=32
It is reduced to 7x / 13-x / 2 = 32
The solution is: x = 832
A: slightly