Car a and car B go from A. to B. car a starts 15 minutes earlier than car B. the speed ratio of car a and car B is 2:3. When they meet, car a walks 6000 less than car B It is known that car a has walked for 1 hour and 45 minutes, and the distance between a and B is calculated It's urgent. Thank you

Car a and car B go from A. to B. car a starts 15 minutes earlier than car B. the speed ratio of car a and car B is 2:3. When they meet, car a walks 6000 less than car B It is known that car a has walked for 1 hour and 45 minutes, and the distance between a and B is calculated It's urgent. Thank you

v1/v2=2/3
That is, 3 * V1 = 2 * v2
And 90 * v2-105 * V1 = 6
The solution is V1 = 0.2km/min, V2 = 0.3km/min
Distance S = 90 * V2 + 105 * V1 = 27 + 21 = 48km

A passenger car and a freight car leave from a and B at the same time. When the two cars meet, the passenger car takes 70% of the whole journey, and the freight car is 320 kilometers away from the midpoint of the two places. It is known that it takes 20 hours for the passenger car to complete the whole journey, and how many kilometers per hour does the passenger car travel

When we met, the truck took the whole journey: 1-70% = 30%
The distance between trucks and the two places is 50% - 30% = 20%
Because there are 320 kilometers between the two places
So the distance between the two places is 320 / 20% = 1600 km
It is known that it takes 20 hours for a bus to complete the whole journey, so the bus can travel (1600 / 20) kilometers per hour
That's 80 kilometers