Party A and Party B set out at the same time and face each other for 1.8h when they are 18km away. If Party A starts 2 / 3H earlier than Party B, they will meet at 1.5h after Party B starts Party A and Party B set out at the same time and face each other for 1.8h when they are 18km away from each other. If Party A starts 2 / 3H earlier than Party B, then they meet at 1.5h after Party B starts to find the speed of Party A and Party B The solution of a series of equations

Party A and Party B set out at the same time and face each other for 1.8h when they are 18km away. If Party A starts 2 / 3H earlier than Party B, they will meet at 1.5h after Party B starts Party A and Party B set out at the same time and face each other for 1.8h when they are 18km away from each other. If Party A starts 2 / 3H earlier than Party B, then they meet at 1.5h after Party B starts to find the speed of Party A and Party B The solution of a series of equations

Speed sum of two persons = 18 △ 1.8 = 10 km / h
So a 2 / 3 hour walk 18-10 × 1.5 = 3km
So the speed of a is 3 △ 2 / 3 = 4.5 km / h
B's speed is 10-4.5 = 5.5 km / h

A. B is 320 kilometers away from each other. Car a and car B are going from a and B at the same time. They meet two hours later. It is known that the speed ratio of car a and car B is 7:9. How many kilometers does car B travel per hour?

320 △ 2 × 97 + 9 = 160 × 916 = 90 (km) a: car B travels 90 km per hour