Two trains a and B leave from a and B which are 500 kilometers apart at the same time. After 2.4 o'clock, the ratio of the distance they have traveled to the distance they have left is three to two. According to this calculation, when will they meet? Fast,

Two trains a and B leave from a and B which are 500 kilometers apart at the same time. After 2.4 o'clock, the ratio of the distance they have traveled to the distance they have left is three to two. According to this calculation, when will they meet? Fast,

Because the ratio of the distance traveled to that of the rest is three to two, the total distance is five
The distance traveled is 500 × 3 / 5 = 300 (km)
The sum of the speed of the two trains is 300 △ 2.4 = 125 (km)
It takes another 500 △ 125-2.4 = 1.6 (hours) to meet

The distance between a and B is 560 km. The two trains leave from the two places at the same time and meet in 4 hours. It is known that the speed of a train is 5 / 4 times that of B train
What's the speed of a and B cars? Because of the new technology adopted by a factory, the cost of each product is 37.4 yuan, which is 15% lower than the original. How much is the original cost of each product?

560/4/(1+5/4)
=140/9/4
=560/9
560/9*5/4
=800/9
A: the speed of a and B is 800 / 9 560 / 9 km / h respectively
37.4/(1-15%)
=37.4/85%
=44
It was 44 yuan per piece,
Please accept!

On the map with a scale of 0-40-80-120km, the distance between a and B is 20cm
55km, 45km per hour, how many hours?

The distance between a and B is 20cm on the map with the scale of 0-40-80-120km. The two trains leave from a and B at the same time. Car a travels 55km per hour and car B 45km per hour. How many hours do they meet? The scale is 1:4000000, so the distance is 20 x 4000000 / 100000 = 800km, and the time is 800