The first train runs 60 kilometers per hour, and the second train runs 50 kilometers per hour Finally, the two cars meet at a distance of 30 kilometers from the midpoint, and the distance between a and B is calculated

The first train runs 60 kilometers per hour, and the second train runs 50 kilometers per hour Finally, the two cars meet at a distance of 30 kilometers from the midpoint, and the distance between a and B is calculated

If you meet at a distance of 30 km from the midpoint, the fast train will travel 30 × 2 = 60 km more than the slow train
Fast trains travel 60-50 km more per hour than local trains
Therefore, the time required for meeting is 60 △ 10 = 6 hours
60 + 50 = 110 km / h
Therefore, the distance between a and B is 110 × 6 = 660 km
Formula: [(30 × 2) / (60-50)] × (60 + 50) = 660km

The first train runs 110 kilometers per hour, and the second train runs 90 kilometers per hour. The two trains meet at 20 kilometers away from the midpoint. How to calculate the time when the two trains meet?

Suppose two cars meet at x hours after departure, 110 * x-90 * x = 40, x = 2

The first train runs 90 kilometers per hour, which is 56 times the speed of the second train. The two trains meet after 83 hours. How many kilometers is the distance between the two cities?

(90 + 90 △ 56) × 83, = (90 + 108) × 83, = 198 × 83, = 528 km. A: the distance between city a and city B is 528 km

The first train is 10 kilometers faster than the second train per hour. The two trains meet at 28 kilometers away from the midpoint of a and B. if the first train leaves 45 minutes later than the original one, the two trains just meet at the midpoint of a and B. the distance between a and B and the speed of the two trains are calculated

Suppose the speed of the first train is x km / h, then the distances between a and B are: 5.6 (x + X-10) = 5.6 (2x-10). According to the meaning of the title, we get 5.6 (2x − 10) 2 (x − 10) − 5.6 (2x − 10) 2x = 0.75, and we get X1 = 143 (not in line with the meaning of the question), X2 = 80. The speed of the second train is X-10 = 80-10 = 70 (km / h); the distances between a and B are: 5.6 (2x-10) = 840 (km). Answer: the speed of the first train The speed of the second train is 70 km / h, and the distance between a and B is 840 km